Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Chapter Test - Page 927: 13

Answer

$x=2$ (hole), $x=-7$ (vertical asymptote).

Work Step by Step

1. Factor to get $R(x)=\frac{x^2(x+6)-4(x+6)}{(x+7)(x-2)} =\frac{(x+6)(x+2)(x-2)}{(x+7)(x-2)}=\frac{(x+6)(x+2)}{x+7}, x\ne2$ 2. Thus the function is undefined at $x=2$ (hole) and $x=-7$ (vertical asymptote).
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