Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Chapter Test - Page 927: 3

Answer

$5$

Work Step by Step

To find the limit, we apply the rule: $\lim\limits_{x \to a} \sqrt {A(x)}= \sqrt {\lim\limits_{x \to a} \ A(x)}$ $\lim\limits_{x \to -6} \sqrt {7-3x}=\sqrt{ \lim\limits_{x \to -6} (7-3x)} \\=\sqrt {7-(3)(-6)} \\=\sqrt {25}\\=5$
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