Answer
$\begin{bmatrix} 6 & 4\\ 1 & -11 \\ 5 & 12 \end{bmatrix}$
Work Step by Step
Given $A=\begin{bmatrix} 1 & -1\\ 0 & -4 \\ 3 & 2 \end{bmatrix}$, $B=\begin{bmatrix} 1 & -2 & 5 \\ 0 & 3 & 1 \end{bmatrix}$, $C=\begin{bmatrix} 4 & 6\\ 1 & -3 \\ -1 & 8 \end{bmatrix}$,
We have:
$2A+C=2\begin{bmatrix} 1 & -1\\ 0 & -4 \\ 3 & 2 \end{bmatrix}+\begin{bmatrix} 4 & 6\\ 1 & -3 \\ -1 & 8 \end{bmatrix}=
\begin{bmatrix} 6 & 4\\ 1 & -11 \\ 5 & 12 \end{bmatrix}$
