Answer
$\{(x,y,z)|y=\frac{-7x+1}{7},z=\frac{-7x+18}{7} \}$ where $x$ is any real number.
Work Step by Step
1. Multiply the 2nd equation by 2 then add to the 1st equation to get $7x+7y=1$
2. Multiply the 2nd equation by 3 then add to the 3rd equation to get $14x+14y=2$ or $7x+7y=1$
3. The above two equations are identical and we have a dependent system and from the 2nd equation we have $z=3x+4y+2=\frac{-7x+18}{7}$
4. Thus the solution $\{(x,y,z)|y=\frac{-7x+1}{7},z=\frac{-7x+18}{7} \}$ where $x$ is any real number.
