Answer
$(\frac{1}{3},-2,0)$.
Work Step by Step
1. Multiply the 2nd equation by 3 then add to the 1st equation to get $-5z=0$, thus $z=0$
2. Multiply the 2nd equation by 6 then add to the 3rd equation to get $-7y=14$, thus $y=-2$
3. Use the 2nd equation to get $x=-\frac{2}{3}y-1=\frac{1}{3}$
4. Thus the solution $(\frac{1}{3},-2,0)$.
