Chapter 10 - Systems of Equations and Inequalities - Chapter Test - Page 816: 10

$\begin{bmatrix} 16 & 17\\ 3 & -10 \end{bmatrix}$

Given $A=\begin{bmatrix} 1 & -1\\ 0 & -4 \\ 3 & 2 \end{bmatrix}$, $B=\begin{bmatrix} 1 & -2 & 5 \\ 0 & 3 & 1 \end{bmatrix}$, $C=\begin{bmatrix} 4 & 6\\ 1 & -3 \\ -1 & 8 \end{bmatrix}$, We have: $BA=\begin{bmatrix} 1 & -2 & 5 \\ 0 & 3 & 1 \end{bmatrix}\times\begin{bmatrix} 1 & -1\\ 0 & -4 \\ 3 & 2 \end{bmatrix}= \begin{bmatrix} 16 & 17\\ 3 & -10 \end{bmatrix}$