Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises - Page 76: 120



Work Step by Step

To solve the item mentally, note that: $\sqrt[6]{2(4)(8)} = \sqrt[6]{64}$ (because of the product rule for radicals) Since $64=2^6$, then $\sqrt[6]{64}=\sqrt[6]{2^6}=2$ Thus, the given expression is equal to $2$
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