Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises - Page 76: 105

Answer

$\sqrt p-2$

Work Step by Step

Multiply $\frac{\sqrt p-2}{\sqrt p-2}$ to the expression, we have: $\frac{p-4}{\sqrt p+2}\cdot \frac{\sqrt p-2}{\sqrt p-2}=\frac{(p-4)(\sqrt p-2)}{p-4}=\sqrt p-2$
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