#### Answer

$2$

#### Work Step by Step

To solve the item mentally, note that:
$\dfrac{\sqrt[5]{320}}{\sqrt[5]{10}} = \sqrt[5]{32}$ (because of the quotient rule for radicals)
Since $32=2^5$. then
$\sqrt[5]{32} = \sqrt[5]{2^5} = 2$
Thus.
$\dfrac{\sqrt[5]{320}}{\sqrt[5]{10}}=2$