Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises - Page 76: 114

Answer

$19^{\circ}F$

Work Step by Step

Given $T_w=35.74+0.6215T-35.75V^{0.16}+0.4275TV^{0.16}$, for $T=30^{\circ}F, V=15 mph$, we have: $T_w=35.74+0.6215(30)-35.75(15)^{0.16}+0.4275(30)(15)^{0.16}\approx19^{\circ}F$
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