Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - 9.1 Systems of Linear Equations - 9.1 Exercises - Page 856: 8



Work Step by Step

1. The second equation has 1 as a coefficient of $x$. solve it for $x$. $x=y+13$ 2. Substitute $x$ in the other equation and solve. $3(y+13)+4y=4$ $3y+39+4y=4 \qquad/ -39$ $7y=-35 \qquad / \div 7$ $y=-5$ 3. Back-substitute into the expression of y (step 1). $x=(-5)+13=8$ 4. Write the solution as an ordered pair. Solution set: $\{(8,-5)\}$
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