## Precalculus (6th Edition)

$\{(0,2)\}$
1. The second equation has 1 as a coefficient of y. solve it for y. $y=2-x$ 2. Substitute y in the other equation and solve. $3(2-x)=5x+6$ $6-3x=5x+6\qquad-6$ $0=8x\qquad/\div 8$ $0=x$ $x=0$ 3. Back-substitute into the expression of y (step 1). $y=2-(0)=2$ 4. Write the solution as an ordered pair. Solution set: $\{(0,2)\}$