Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - 9.1 Systems of Linear Equations - 9.1 Exercises - Page 856: 7



Work Step by Step

1. The second equation has 1 as a coefficient of y. solve it for y. $y=x+5$ 2. Substitute $(x+5)$ for y in the other equation and solve. $4x+3(x+5)=-13$ $4x+3x+15=-13\qquad-15$ $7x=-28\qquad\div 7$ $x=-4$ 3. Back-substitute into the expression of y (step 1). $y=(-4)+5=1$ 4. Write the solution as an ordered pair. Solution set: $\{(-4,1)\}$
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