#### Answer

$\{(1,3)\}$

#### Work Step by Step

1. The second equation has 1 as a coefficient of y. Solve it for y.
$y=6-3x$
2. Substitute y in the other equation and solve.
$8x-10(6-3x)=-22$
$8x-60+30x=-22\qquad/+60$
$38x=38\qquad/\div 38$
$x=1$
3. Back-substitute into the expression of y (step 1).
$y=6-3(1)=3$
4. Write the solution as an ordered pair.
Solution set: $\{(1,3)\}$