Answer
$\lt 4.10, -2.87 \gt $
Work Step by Step
Let $v$ is a vector that has a magnitude $|v|$ and the direction angle of $\theta$.
Firstly, we need to convert the given angle to standard position.
That is, $ \theta =360^{\circ}- 35^{\circ} = 325^{\circ}$
The magnitude of horizontal component is given by: $v_x=|v| \cos \theta= 5 \cos 325^{\circ}= 4.10$
And
The magnitude of vertical component is given by: $v_y=|v| \sin \theta= 5 \sin 325^{\circ}= -2.87$
Thus, $v=\lt 4.10, -2.87 \gt $