Answer
$\lt 3.06, 2.57 \gt $
Work Step by Step
Let $v$ is a vector that has a magnitude $|v|$ and the direction angle of $\theta$.
The magnitude of horizontal component is given by: $v_x=|v| \cos \theta= 4 \cos 40^{\circ}=3.06$
And
The magnitude of vertical component is given by: $v_y=|v| \sin \theta=4 \sin 40^{\circ}= 2.57$
Thus, $v=\lt 3.06, 2.57 \gt $