Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - 8.4 Algebraically Defined Vectors and the Dot Product - 8.4 Exercises - Page 789: 18

Answer

$-198.01$ and $132.05$

Work Step by Step

Let $v$ is a vector that has a magnitude $|v|$ and the direction angle of $\theta$. The magnitude of horizontal component is given by: $v_x=|v| \cos \theta= 238 \cos 146.3^{\circ}=-198.01$ And The magnitude of vertical component is given by: $v_y=|v| \sin \theta=238 \sin 146.3^{\circ}=132.05$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.