Answer
$\lt 4.33, 2.50 \gt $
Work Step by Step
Let $v$ is a vector that has a magnitude $|v|$ and the direction angle of $\theta$.
The magnitude of horizontal component is given by: $v_x=|v| \cos \theta= 5 \cos 30^{\circ}=4.33$
And
The magnitude of vertical component is given by: $v_y=|v| \sin \theta=5 \sin 30^{\circ}=2.50$
Thus, $v=\lt 4.33, 2.50 \gt $
