Answer
$13.66$ and $7.11$
Work Step by Step
Let $v$ is a vector that has a magnitude $|v|$ and the direction angle of $\theta$.
The magnitude of horizontal component is given by: $v_x=|v| \cos \theta= 15.4 \cos 27^{\circ} 30'=13.66$
And
The magnitude of vertical component is given by: $v_y=|v| \sin \theta=15.4 \sin 27^{\circ} 30'=7.11$
