Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - Quiz - Page 683: 9



Work Step by Step

$\dfrac {\sin ^{2}\theta -\cos ^{2}\theta }{\sin ^{4}\theta -\cos ^{4}\theta }=\dfrac {\sin ^{2}\theta -\cos ^{2}\theta }{\left( \sin ^{2}\theta -\cos ^{2}\theta \right) \left( \sin ^{2}\theta +\cos ^{2}\theta \right) }=\dfrac {1}{\sin ^{2}\theta +\cos ^{2}\theta }=\dfrac {1}{1}=1$
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