Answer
See below for answers.
Work Step by Step
Given $sin\theta=-\frac{7}{25}$ and $\theta$ in quadrant IV, form a right triangle with sides $7, 24,25$ and the side facing $\theta$ be $7$, we have:
1. $cos\theta=\frac{24}{25}$
2. $tan\theta=-\frac{7}{24}$
3. $cot\theta=-\frac{24}{7}$
4. $sec\theta=\frac{1}{cos\theta}=\frac{25}{24}$
5. $csc\theta=\frac{1}{sin\theta}=-\frac{25}{7}$