#### Answer

$\dfrac {1+\cos ^{2}x}{\sin ^{2}x}$

#### Work Step by Step

$\cot ^{2}x+csc^{2}x=\dfrac {\cos ^{2}x}{\sin ^{2}x}+\dfrac {1}{\sin ^{2}x}=\dfrac {1+\cos ^{2}x}{\sin ^{2}x}$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$\dfrac {1+\cos ^{2}x}{\sin ^{2}x}$

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