Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - Quiz - Page 683: 6


$\dfrac {\tan x-1}{\tan x+1}$

Work Step by Step

$\tan \left( \dfrac {3\pi }{4}+x\right) =\dfrac {\tan \dfrac {3\pi }{4}+\tan x}{1-\tan \dfrac {3\pi }{4}\tan x}=\dfrac {-1+\tan x}{1-\left( -1\right) \times \tan x}=\dfrac {\tan x-1}{\tan x+1}$
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