Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - Chapter 7 Test Prep - Review Exercises - Page 738: 99


$\dfrac {\sqrt {7}}{4}$

Work Step by Step

$\sin \left( \arccos x\right) =\sqrt {1-x^{2}}\Rightarrow \sin \left( \arccos \dfrac {3}{4}\right) =\sqrt {1-\left( \dfrac {3}{4}\right) ^{2}}=\dfrac {\sqrt {7}}{4}$
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