Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - Chapter 7 Test Prep - Review Exercises - Page 738: 73



Work Step by Step

The statement is false because $\frac{11\pi}{6}$ is not in the range of $\arcsin x$. Since $\arcsin x$ is the value of $x$ in the interval $\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]$ whose sine is $x$, $\arcsin (-\frac{1}{2})=-\frac{\pi}{6}$.
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