## Precalculus (6th Edition)

Published by Pearson

# Chapter 7 - Trigonometric Identities and Equations - Chapter 7 Test Prep - Review Exercises - Page 738: 75

#### Answer

$\frac{\pi}{4}$

#### Work Step by Step

We know that $y=\arcsin x$ means $y$ is the value in the interval $\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]$ whose sine is $x$. The solutions to $\sin y=\frac{\sqrt{2}}{2}$ are $y=..., -\frac{7\pi}{4}, -\frac{5\pi}{4}, \frac{\pi}{4}, \frac{3\pi}{4}, \frac{9\pi}{4}, \frac{11\pi}{4}, ...$. The only solution in the interval $\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]$ is $y=\frac{\pi}{4}$. Therefore, the solution to $y=\arcsin \frac{\sqrt{2}}{2}$ is $y=\frac{\pi}{4}$.

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