Answer
$\sec^{2}\theta$
Work Step by Step
$\displaystyle \frac{\sin^{2}\theta}{\cos^{2}\theta}(1+\frac{\cos^{2}\theta}{\sin^{2}\theta})=\frac{\sin^{2}\theta}{\cos^{2}\theta}+\frac{\sin^{2}\theta}{\cos^{2}\theta}\times\frac{\cos^{2}\theta}{\sin^{2}\theta}$
$=\displaystyle \frac{\sin^{2}\theta}{\cos^{2}\theta}+1$
$=\displaystyle \frac{\sin^{2}\theta+\cos^{2}\theta}{\cos^{2}\theta}$
$=\displaystyle \frac{1}{\cos^{2}\theta}$
$=(\displaystyle \frac{1}{\cos\theta})^{2}$
$=\sec^{2}\theta$