Answer
$\sec^{2}\theta\cdot\csc^{2}\theta$
Work Step by Step
$\displaystyle \csc^{2}\theta+\sec^{2}\theta=\frac{1}{\sin^{2}\theta}+\frac{1}{\cos^{2}\theta}$
... common denominator: $\cos^{2}\theta\sin^{2}\theta$ ...
$=\displaystyle \frac{\cos^{2}\theta+\sin^{2}\theta}{\cos^{2}\theta\sin^{2}\theta}$
$=\displaystyle \frac{1}{\cos^{2}\theta\sin^{2}\theta}$
$=\displaystyle \frac{1}{\cos^{2}\theta}\times\frac{1}{\sin^{2}\theta}$
$=\sec^{2}\theta\cdot\csc^{2}\theta$
