#### Answer

$H$

#### Work Step by Step

$\tan \left( -35\right) =\cot \left( 90-\left( -35\right) \right) =\cot 125^0$
$19\rightarrow H$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$H$

$\tan \left( -35\right) =\cot \left( 90-\left( -35\right) \right) =\cot 125^0$
$19\rightarrow H$

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