Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - Chapter 7 Test Prep - Review Exercises - Page 736: 7



Work Step by Step

$sec^2\theta -\tan ^{2}\theta =\dfrac {1}{\cos ^{2}\theta }-\dfrac {\sin ^{2}\theta }{\cos ^{2}\theta }=\dfrac {1-\sin ^{2}\theta }{\cos ^{2}\theta }=\dfrac {\cos ^{2}\theta }{\cos ^{2}\theta }=1$
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