#### Answer

$1$

#### Work Step by Step

$sec^2\theta -\tan ^{2}\theta =\dfrac {1}{\cos ^{2}\theta }-\dfrac {\sin ^{2}\theta }{\cos ^{2}\theta }=\dfrac {1-\sin ^{2}\theta }{\cos ^{2}\theta }=\dfrac {\cos ^{2}\theta }{\cos ^{2}\theta }=1$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$1$

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