Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.6 Trigonometric Equations - 7.6 Exercises - Page 720: 27


Solution set: $\{30^{o},210^{o},240^{o},300^{o}\}$

Work Step by Step

Using the zero product principle, either 1. $\quad \cot\theta-\sqrt{3}=0\quad$or 2. $\quad 2\sin+\sqrt{3=0.}$ 1. $\quad \cot\theta=\sqrt{3}$ $\theta=30^{o}\quad$or $\theta=30^{0}+180^{o}=210^{o}$ $2.\quad 2\sin\theta=-\sqrt{3}\quad/\div 2$ $\displaystyle \sin\theta=-\frac{\sqrt{3}}{2}$ ... use the unit circle, y coordinate = $-\displaystyle \frac{\sqrt{3}}{2}$... $\theta=240^{o} \quad$ or $\theta=300^{o}$ Solution set: $\{30^{o},210^{o},240^{o},300^{o}\}$
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