## Precalculus (6th Edition)

$\frac{\pi}{6}$, $\frac{5\pi}{6}$
$2\sin x+3=4$ $2\sin x=1$ $\sin x=\frac{1}{2}$ Referring to the unit circle and remembering that sine is positive in Quadrants I and II, we conclude that the only solutions in $[0, 2\pi)$ are $\frac{\pi}{6}$ and $\frac{5\pi}{6}$.