Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.6 Trigonometric Equations - 7.6 Exercises - Page 720: 11



Work Step by Step

As solved in exercise $5$, the angle (degree measures) with sine equal to $-1$ is$ 270^{o}$. Also, if $0 \leq \theta < 360^{o}\qquad/\div 2$ then $0 \displaystyle \leq \frac{\theta}{2} < 180^{o}.$ But, $\displaystyle \frac{\theta}{2}= 270^{o}$ is not in the interval $0 \displaystyle \leq \frac{\theta}{2} < 180^{o}$. There are no solutions in the interval $0 \leq \theta < 360^{o}$. Solution set: $\emptyset.$
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