Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.6 Trigonometric Equations - 7.6 Exercises - Page 720: 2


$\displaystyle \{\frac{\pi}{6}, \ \ \frac{11\pi}{6}\}$

Work Step by Step

For a point on the unit circle, the coordinates are ($\cos x,\sin x)$, $x\in[0,2\pi)$ To solve the problem, find the points for which the x-coordinate is $\displaystyle \frac{\sqrt{3}}{2}$, ($\cos x$=$\displaystyle \frac{\sqrt{3}}{2}$) Using the given unit circle, we find such points in quadrant I, for $x=\displaystyle \frac{\pi}{6}$ in quadrant IV, for $x=\displaystyle \frac{11\pi}{6}$ Solution set: $\displaystyle \{\frac{\pi}{6}, \ \ \frac{11\pi}{6}\}$
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