# Chapter 7 - Trigonometric Identities and Equations - 7.5 Inverse Circular Functions - 7.5 Exercises - Page 708: 38

$60^{o}$

#### Work Step by Step

Solve for radians, then convert to degrees. $y=\tan^{-1} x$ Domain: $(-\infty, \infty)$ Range: $(-\displaystyle \frac{\pi}{2}, \displaystyle \frac{\pi}{2})$ ------------- $y$ is the number from $(-\displaystyle \frac{\pi}{2}, \displaystyle \frac{\pi}{2})$ such that $\tan y=\sqrt3$ $\displaystyle \tan(\frac{\pi}{3})=\sqrt{3}\qquad$and$\displaystyle \quad \frac{\pi}{3}\in(-\frac{\pi}{2}, \displaystyle \frac{\pi}{2})$, so $y =\displaystyle \frac{\pi}{3}$ To convert radians to degrees, multiply y with $\displaystyle \frac{180^{o}}{\pi}$ $\displaystyle \theta=\frac{\pi}{3}\cdot\frac{180^{o}}{\pi}=60^{o}$

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