Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.5 Inverse Circular Functions - 7.5 Exercises - Page 708: 16


$\displaystyle \frac{\pi}{2}$

Work Step by Step

$y=\cos^{-1}x =\arccos x$ Domain:$[-1, 1] $ Range: $[0, \pi]$ ----------- $y$ is the number from $[0, \pi]$ such that $\cos y=0$ $\displaystyle \cos\frac{\pi}{2}=0,\quad$and $\displaystyle \frac{\pi}{2}\in [0, \pi]$, so $\displaystyle \arccos(0)=\frac{\pi}{2}$
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