Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.5 Inverse Circular Functions - 7.5 Exercises: 13

Answer

$\sin^{-1}0=0$

Work Step by Step

$y=\sin^{-1}x$ Domain: $[-1, 1] $, Range:$ [-\displaystyle \frac{\pi}{2}, \displaystyle \frac{\pi}{2}]$ meaning: "$y$ is the number from $[-\displaystyle \frac{\pi}{2}, \displaystyle \frac{\pi}{2}]$ such that $\sin y=x$" ---------------- $\sin 0=0$, and $0\displaystyle \in[-\frac{\pi}{2}, \displaystyle \frac{\pi}{2}]$ so $\sin^{-1}0=0$
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