Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.2 Trigonometric Functions - 5.2 Exercises - Page 518: 2

Answer

$-\frac{\sqrt 2}{2}$

Work Step by Step

$r=\sqrt {(-3)^{2}+(-3)^{2}}=3\sqrt 2$ $\sin\theta=\frac{y}{r}=\frac{-3}{3\sqrt 2}=-\frac{1}{\sqrt 2}=-\frac{\sqrt 2}{2}$
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