Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.2 Trigonometric Functions - 5.2 Exercises - Page 518: 12

Answer

See sketch, $sin\theta= -\frac{5}{13}$, $cos\theta= -\frac{12}{13}$, $tan\theta= \frac{5}{12}$, $cot\theta= \frac{12}{5}$, $sec\theta= -\frac{13}{12}$, $csc\theta= -\frac{13}{5}$

Work Step by Step

1. See sketch. 2. We can find $sin\theta=\frac{-5}{\sqrt {(-5)^2+(-12)^2}}=-\frac{5}{13}$ 3. We can find $cos\theta=\frac{-12}{\sqrt {(-5)^2+(-12)^2}}=-\frac{12}{13}$ 4. We can find $tan\theta=\frac{-5}{-12}=\frac{5}{12}$ 5. We can find $cot\theta=\frac{-12}{-5}=\frac{12}{5}$ 6. We can find $sec\theta=\frac{1}{cos\theta}=-\frac{13}{12}$ 7. We can find $csc\theta=\frac{1}{sin\theta}=-\frac{13}{5}$
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