Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.2 Trigonometric Functions - 5.2 Exercises - Page 518: 16

Answer

See sketch, $sin\theta= -\frac{8}{17}$, $cos\theta= \frac{15}{17}$, $tan\theta= -\frac{8}{15}$, $cot\theta= -\frac{15}{8}$, $sec\theta= \frac{17}{15}$, $csc\theta= -\frac{17}{8}$

Work Step by Step

1. See sketch. 2. We can find $sin\theta=\frac{-8}{\sqrt {(15)^2+(-8)^2}}=-\frac{8}{17}$ 3. We can find $cos\theta=\frac{15}{\sqrt {(15)^2+(-8)^2}}=\frac{15}{17}$ 4. We can find $tan\theta=\frac{-8}{15}=-\frac{8}{15}$ 5. We can find $cot\theta=\frac{15}{-8}=-\frac{15}{8}$ 6. We can find $sec\theta=\frac{1}{cos\theta}=\frac{17}{15}$ 7. We can find $csc\theta=\frac{1}{sin\theta}=-\frac{17}{8}$
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