Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.2 Trigonometric Functions - 5.2 Exercises - Page 518: 14

Answer

See sketch, $sin\theta= -\frac{3}{5}$, $cos\theta= -\frac{4}{5}$, $tan\theta= \frac{3}{4}$, $cot\theta=\frac{4}{3}$, $sec\theta= -\frac{5}{4}$, $csc\theta= -\frac{5}{3}$

Work Step by Step

1. See sketch. 2. We can find $sin\theta=\frac{-3}{\sqrt {(-4)^2+(-3)^2}}=-\frac{3}{5}$ 3. We can find $cos\theta=\frac{-4}{\sqrt {(-4)^2+(-3)^2}}=-\frac{4}{5}$ 4. We can find $tan\theta=\frac{-3}{-4}=\frac{3}{4}$ 5. We can find $cot\theta=\frac{-4}{-3}=\frac{4}{3}$ 6. We can find $sec\theta=\frac{1}{cos\theta}=-\frac{5}{4}$ 7. We can find $csc\theta=\frac{1}{sin\theta}=-\frac{5}{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.