Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.1 Angles - 5.1 Exercises - Page 504: 45

Answer

$38^\circ 32'$

Work Step by Step

In this kind of subtraction, we subtract the degrees from the degrees and the minutes from the minutes: $90^\circ$ can be rewritten as: $89^\circ 60'$ $89^\circ 60'-51^\circ 28'=(89-51)^\circ+(60-28)'=38^\circ 32'$
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