Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.1 Angles - 5.1 Exercises - Page 504: 24


$(20x+10)^\circ=150^\circ$ $(3x+9)^\circ=30^\circ$

Work Step by Step

The sum of the two angle is a straight angle ($180^\circ$): $(20x+10)^\circ+(3x+9)^\circ=(23x+19x)^\circ=180^\circ$ $23x+19=180$ $23x=180-19=161$ $x=7$ $(20x+10)^\circ=150^\circ$ $(3x+9)^\circ=30^\circ$
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