Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.1 Angles - 5.1 Exercises - Page 504: 31


$(9x+6)^\circ=69^\circ$ $(3x)^\circ=21^\circ$

Work Step by Step

If two angles are complementary, the sum of the two angles is a right angle ($90^\circ$): $(9x+6)^\circ+(3x)^\circ=(12x+6)^\circ=90^\circ$ $12x+6=90$ $12x=84$ $x=7$ $(9x+6)^\circ=69^\circ$ $(3x)^\circ=21^\circ$
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