## Precalculus (6th Edition)

$(5x+5)^\circ=55^\circ$ $(3x+5)^\circ=35^\circ$
The sum of the two angles is a right angle ($90^\circ$): $(5x+5)^\circ+(3x+5)^\circ=(8x+10x)^\circ=90^\circ$ $8x+10=90$ $x=10$ $(5x+5)^\circ=55^\circ$ $(3x+5)^\circ=35^\circ$