Answer
$f^{-1}(x)=e^{x-6}+1$, domain $(-\infty,\infty)$, rang $(1,\infty)$
Work Step by Step
Step 1. Find the inverse: $y=ln{(x-1)}+6 \longrightarrow x=e^{y-6}+1 \longrightarrow f^{-1}(x)=e^{x-6}+1$
Steo 2. For $f^{-1}(x)=e^{x-6}+1$, we can find domain $(-\infty,\infty)$, rang $(1,\infty)$