Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises - Page 472: 116

Answer

$f^{-1}(x)=e^x-2$, domain $(-\infty,\infty)$, rang $(-2,\infty)$

Work Step by Step

Step 1. Find the inverse: $y=ln{x+2} \longrightarrow x=e^y-2 \longrightarrow f^{-1}(x)=e^x-2$ Steo 2. For $f^{-1}(x)=e^x-2$, we can find domain $(-\infty,\infty)$, rang $(-2,\infty)$
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