Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises - Page 472: 114

Answer

$f^{-1}(x)=ln(x-10)$, domain $(10,\infty)$, rang $(-\infty,\infty)$

Work Step by Step

Step 1. Find the inverse: $y=e^{x}+10 \longrightarrow x=ln(y-10) \longrightarrow f^{-1}(x)=ln(x-10)$ Steo 2. For $f^{-1}(x)=ln(x-10)$, we can find domain $(10,\infty)$, rang $(-\infty,\infty)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.