Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises - Page 472: 113

Answer

$ f^{-1}(x)=ln(x)+5$, domain $(0,\infty)$, rang $(-\infty,\infty)$

Work Step by Step

Step 1. Find the inverse: $y=e^{x-5} \longrightarrow x=ln(y)+5 \longrightarrow f^{-1}(x)=ln(x)+5$ Steo 2. For $ f^{-1}(x)=ln(x)+5$, we can find domain $(0,\infty)$, rang $(-\infty,\infty)$
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