Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises - Page 470: 97

Answer

$t=\dfrac{\log \dfrac{A}{P}}{n \log (a+\dfrac{r}{n})}$

Work Step by Step

The given expression can be written as: $\dfrac{A}{P}=(a+\dfrac{r}{n})^{tn}$ We need to take log of both sides and apply logarithmic property : $\log a^ b=b \log a$ . $ \log \dfrac{A}{P}=tn \log (a+\dfrac{r}{n})$ Therefore, our answer is: $t=\dfrac{\log \dfrac{A}{P}}{n \log (a+\dfrac{r}{n})}$
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